j^2+20j+19=0

Solution for j^2+20j+19=0 equation:

Simplifying
j2 + 20j + 19 = 0

Reorder the terms:
19 + 20j + j2 = 0

Solving
19 + 20j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(19 + j)(1 + j) = 0

Subproblem 1
Set the factor '(19 + j)' equal to zero and attempt to solve:

Simplifying
19 + j = 0

Solving
19 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + j = 0 + -19

Combine like terms: 19 + -19 = 0
0 + j = 0 + -19
j = 0 + -19

Combine like terms: 0 + -19 = -19
j = -19

Simplifying
j = -19
Subproblem 2
Set the factor '(1 + j)' equal to zero and attempt to solve:

Simplifying
1 + j = 0

Solving
1 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + j = 0 + -1
j = 0 + -1

Combine like terms: 0 + -1 = -1
j = -1

Simplifying
j = -1
Solution
j = {-19, -1}